KUIS
[tex] \displaystyle\int\limits^{2}_{0.5}( \sf2x + x) = [/tex]
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jawabanku lucu/ngelawak gk? terhibur gk?
[tex] \displaystyle\int\limits^{2}_{0.5}( \sf2x + x) = [/tex]
______________
jawabanku lucu/ngelawak gk? terhibur gk?
Jawaban:
5 5/8
Penjelasan dengan langkah-langkah:
Integralkan 3x:
[tex] = \int3x \\ = \frac{3}{2} {x}^{2} [/tex]
Maka:
= 3/2(2)²-3/2(0.5)²
= 3/2(4)-3/2(1/4)
= 6-3/8
= 5 5/8
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